How can I factorize an equation like 3xy-1-3x+y?
Also, if someone could do (x²-x-2)/(x-2) and leave their traces. Thanks.
How can I factorize an equation like 3xy-1-3x+y?
Also, if someone could do (x²-x-2)/(x-2) and leave their traces. Thanks.
I need someone to explain this simply.
Zeno states that for motion to occur, an object must change the position which it occupies. He gives an example of an arrow in flight. He states that in any one (durationless) instant of time, the arrow is neither moving to where it is, nor to where it is not.[11] It cannot move to where it is not, because no time elapses for it to move there; it cannot move to where it is, because it is already there. In other words, at every instant of time there is no motion occurring. If everything is motionless at every instant, and time is entirely composed of instants, then motion is impossible.
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What would the answers to these be?
Find the slope and y-intercept of each equation
y=2/3x +1
y= -x - 7
The red one is subtract
y= -3/4x - 5
The red one means subtract
Please help me with these I need to complete this to pass algebra.
"I'm just a passing through Pokemon Trainer,"
generally Gradient equations are set out in this manner
Y = (Gradient)X +/- (Y intercept)
so numbers in front of the x are the gradients(slopes) and the integers are the y intercept;
1. y=2/3x +1 so gradient is 2/3 and y intercept is 1
2. y= -(1)x - 7 so gradient is -1 and y intercept is -7
you can try the last one yourself so you learn instead of me giving you the answers
Anyone here any good with Pascal?
I need help with my Pre-Cal homework.
The problem I'm working on is:
Perform the indicated operation and use the fundamental identities to simplify.
(24/sec(X)+1)- 24/sec(x)-1
I know that I have to multiply by the other denominator and I'm pretty sure the denominator of the next step is (sec(x) +1)(sec(x)1)
I'm not sure if I should distribute or keep 24(secx-1) or 24(secx+1). If your interested, I could really use the help.
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Sorry, if it's late, but people can still learn and the problem is: ((24)/(sec(x)+1))-((24)/(sec(x)-1))
Right? This is how I would insert it into my calculator. My mind thought part of it said "((24)/(sec(x)))-1". I use too much paratheses; maybe I should use some brackets.
I would, after multiplying the numerator by the other denominator, try taking out 24. It would eventually become (-48)/(sec(x)+1)(sec(x)-1) because you would multiply secant x plus one by the negative one that was left behind when you took out 24. Negative secant plus positive equals zero and negative one minus one equals negative two. Then, multiply -2 by 24.
Distributing and then solving takes longer than just taking out the common factor. I like cancelling before-hand.
Ah, thanks.
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Is this project still ongoing? If it is, I'll sign up as a tutor.
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I guess it happens because things like zero and infinity don't really exist, but are rather used to better describe the other phenomena (like functions).
That is, there is not a "moment" for real, let alone that all "instants" form the whole. They can help in certain situations, but don't really exist.
I hope I can answer despite I'm not a tutor yet.
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